Dynamics & Control · Lab

Root Locus Lab

Enter the base system G(s) as polynomial coefficients or directly as ω_n and ζ, then move the scalar gain. The locus shows where the closed-loop poles of 1 + K·G(s) = 0 travel; the panels show exactly what the current gain does to stability and to the response.

Base system G(s)

Numerator N(s) · degree 0
Denominator D(s) · degree 2
+
+

loop L(s) = K · G(s) with K = 1
characteristic equation 1 + K·G(s) = 0 → D(s) + K·N(s) = 0
closed loop T(s) = K·N(s) / [D(s) + K·N(s)]

Examples

Gain K

Read as the classical locus parameter: the swept scalar multiplies G(s) in L(s) = K·G(s). Switch to proportional control to read the same number as a controller gain.

K = 0log scale from 0.1K = 1000
Gain range

Range in use: 0 … 1000. The automatic range is large enough for finite-zero convergence and asymptotic behaviour, and it always contains every stability crossing that was found.

Current lower bound 0.

Root-locus properties

Branches (n)2
Finite zeros (m)0
Branches to infinity (n − m)2
Asymptote centroid σ_a0
Asymptote angles90°, 270°
Open-loop poles and zeros
  • × pole s = 0 + 1.414j
  • × pole s = 0 − 1.414j
  • No finite zeros.
Real-axis segments
  • No part of the real axis is on the locus.
Breakaway / break-in points (0)
  • No verified break point: dK/ds = 0 has no real solution on a positive-gain segment here.
Rejected candidates (1)
  • s = 0 · rejected — Not on a positive-K real-axis locus segment.
Departure and arrival angles
  • departure from 0 + 1.414j · 90°
  • departure from 0 − 1.414j · 270°

Key points

Starts at K = 0
  • ✕ open-loop pole s = 0 + 1.414j
  • ✕ open-loop pole s = 0 − 1.414j
Ends as K → ∞
  • 2 branch(es) leave along the asymptotes from σ_a = 0
Break points
  • None on the positive-gain locus.
Imaginary-axis crossings
  • None in the gain range examined: the locus stays on one side of Re(s) = 0.

Angle and magnitude conditions

Angle condition. A point s belongs to the positive-K locus when the open-loop phase satisfies ∠G(s) = (2l + 1)·180° — the phase contributed by the zeros minus the phase contributed by the poles is an odd multiple of 180°.

Magnitude condition. The gain at such a point follows from |K·G(s)| = 1, i.e. K = 1/|G(s)|. Every branch point plotted here obeys both conditions by construction: it is a root of D(s) + K·N(s).

Root locus — 1 + K·G(s) = 0

View
The window follows the system geometry; the gain never moves the axes.
Legend
  • ✕ open-loop poles (2)
  • ■ closed-loop poles at K = 1
  • — locus branches
  • ┄ asymptotes
  • ✛ centroid σ_a = 0
  • ┆ stability boundary Re(s) = 0; shaded side is unstable
Display

Closed-loop poles at the current gain

Gain K1
Closed-loop verdictMarginally stable
Right-half-plane poles0
Imaginary-axis poles2
Dominant Re(s)0
Closed-loop poles — roots of D(s) + K·N(s)
PoleRe(s)Im(s)Half-plane
■ 101.732On the axis
■ 20-1.732On the axis
Closed-loop second-order reading at K = 1
RegimeUndamped (ζ = 0)
ω_n1.732 rad/s
ζ0
ω_d1.732 rad/s
Percent overshootNot defined
Settling time (2%, envelope)Not applicable in this regime

These metrics are reported only because the closed loop really is the canonical second-order form here: a degree-2 characteristic polynomial with no closed-loop zero. Add a zero or a third pole and they disappear rather than being approximated.

Closed-loop response T(s) = K·G/(1 + K·G)

Time view
output solid · horizon 22 s
Final value y∞The final-value theorem requires every pole of s·Y(s) in the open left half-plane; this system is not asymptotically stable, so no finite steady state exists.Not applicable
Peak value0.6667
Peak time16.32 s
Percent overshootThe final-value theorem requires every pole of s·Y(s) in the open left half-plane; this system is not asymptotically stable, so no finite steady state exists.Not applicable
Settling time (2%)The final-value theorem requires every pole of s·Y(s) in the open left half-plane; this system is not asymptotically stable, so no finite steady state exists.Not applicable
Settling time (5%)The final-value theorem requires every pole of s·Y(s) in the open left half-plane; this system is not asymptotically stable, so no finite steady state exists.Not applicable
Rise time (10%–90%)The final-value theorem requires every pole of s·Y(s) in the open left half-plane; this system is not asymptotically stable, so no finite steady state exists.Not applicable

Stability range in K

  • 0 ≤ K (up to the largest gain examined) · marginal
Imaginary-axis crossings
  • No crossing was found in the gain range examined.
Select a gain

This system has no special gain to jump to.

These are computed landmarks, not recommendations: root locus is an analysis tool and there is no universal optimal gain.

Loop frequency summary — L(s) = K·G(s)

Gain crossover ω_gc1.732 rad/s
Phase margin0°
Gain margin0.5346 dB

The full Bode and Nyquist workspace lives in the Transfer Function Lab; this is a compact reading of the current loop only.

Continue with this system

The current model travels with the link; nothing is re-entered and nothing opens on its own.

The gain travels as part of the loop numerator, so it means the same thing in every workspace: the loop analysed there is exactly K·G(s), while the plant links carry the untouched G(s).

Diagnostics

Diagnostics

  • · Info Simple poles on the imaginary axis give a bounded, non-decaying mode: the system is marginally stable, not asymptotically stable.
  • ⚠ Note More than 20 -180° crossings were found in this range; only the first 20 are listed. Narrow the frequency range to inspect the rest.
  • ⚠ Note The loop magnitude crosses 0 dB at 2 frequencies, so a single phase margin does not characterise it. Every candidate is listed.
  • ⚠ Note The loop phase crosses -180° (modulo 360°) at 20 frequencies, so several gain-margin candidates exist.

What this Lab models

The closed-loop pole trajectories of 1 + K·G(s) = 0 as the scalar gain K varies: real-axis segments, asymptotes, breakaway points, imaginary-axis crossings, the stable gain interval(s) and the resulting closed-loop response at the selected K.

Related calculations