Calculator · Electrical Engineering
Parallel-Plate Capacitor Calculator
Two flat plates of area A a distance d apart, with a dielectric of relative permittivity εr between them. The ideal model assumes a uniform field and neglects fringing at the edges.
Inputs
Results
Capacitance C = εr·ε0·A/d
885.4 pF
| Absolute permittivity ε = εr·ε0 | 8.854 pF/m |
|---|---|
| Vacuum permittivity ε0 | 8.8541878128 pF/m |
| Charge Q = C·V | 88.54 nC |
| Field E = V/d | 1 MV/m |
| Stored energy U = ½·C·V² | 4.427 µJ |
| Energy density u = ½·ε·E² | 4.427 J/m³ |
Assumptions
- · uniform field between the plates
- · fringing at the plate edges neglected
- · linear, isotropic dielectric filling the gap
Explore in the Lab
Open this capacitor in the Capacitors & Transients Lab
The Lab holds C at the voltage V, so it stores the same energy.
Technical reference
C = εr·ε0·A/d
Q = C·V, E = V/d
U = ½·C·V² = ½·ε·E²·(A·d)
- A
- plate area (> 0)[m²]
- d
- plate separation (> 0)[m]
- εr
- relative permittivity (≥ 1)[–]
- ε0
- vacuum permittivity 8.8541878128 × 10⁻¹² F/m[F/m]
Accurate when d is small compared with the plate size, so fringing is negligible.
Dielectric breakdown is not checked.